Question

The glucose meter measures the current produced during reaction 3. If 0.67 umol of electrons were measured, what mass of glucose was present in the sample. Note the molar mass of glucose is 180 g/mol or 180 ug/umol

a) 20 ug
b) 60 ug
c) 90 ug
d) 270 ug

Answer 1

The mass of glucose present in the sample is 20 ug.

Step-by-step explanation:

The glucose meter measures the current produced during reaction 3. If 0.67 umol of electrons were measured, we can use the molar mass of glucose to calculate the mass of glucose present in the sample.

First, we convert the measured number of electrons to moles of electrons by dividing by Avogadro's number (6.022 x 10^23). Then, we use the molar ratio between electrons and glucose from the reaction to calculate the moles of glucose present. Finally, we convert the moles of glucose to mass using the molar mass.

In this case, 0.67 umol of electrons is equal to 0.67 umol x (1 mol glucose / 6 mol electrons) x (180 g glucose / 1 mol glucose) = 0.67 umol x (180 g / 6 x 6.022 x 10^23) = 0.67 umol x 0.3 x 10^-6 g = 0.2 x 10^-6 g = 20 ug of glucose.