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Given the balanced equation representing a reaction: 2C0(9) + 02(9) → 2C02(9) What is the mole ratio of CO(g) to CO2(g) in this reaction?

User DeltaTango
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Final Answer:

The mole ratio of CO(g) to CO2(g) in the given reaction is 2:2 or 1:1. In the balanced chemical equation \(2CO_2(g) + O_2(g) \rightarrow 2CO_2(g)\), the coefficients represent the stoichiometric coefficients, indicating the mole ratios of the reactants and products. For CO(g) and CO2(g), the coefficients are both 2.

Step-by-step explanation:

This means that two moles of CO react to produce two moles of CO2. Therefore, the mole ratio of CO(g) to CO2(g) is 2:2 or simplified to 1:1.

To understand this conceptually, consider that chemical equations must be balanced to satisfy the law of conservation of mass. The coefficients in a balanced equation indicate the relative amounts of each substance involved in the reaction. In this case, for every two moles of CO consumed, two moles of CO2 are produced. The ratio remains constant regardless of the actual amounts involved, ensuring that the reaction conserves mass.

In mathematical terms, if \(a\) moles of CO react, the balanced equation indicates that \(a\) moles of CO2 will be produced. This relationship is established by the coefficients in the balanced equation, and in this case, the mole ratio is 1:1. In conclusion, the mole ratio of CO(g) to CO2(g) in the given reaction is 1:1, as indicated by the balanced chemical equation.

User Noxious Reptile
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