(i) The horizontal distance traveled by the jumper 1,272.53 m.
(ii) The velocity of the jumper after 0.5 s is 117.6 m/s.
How to calculate the horizontal distance of the jumper?
(i) The horizontal distance traveled by the jumper is calculated by applying the following formula as shown below.
R = (u² sin (2θ) ) / g
where;
- u is the initial velocity of the jumper
- θ is the angle of projection
- g is acceleration due to gravity
R = (120² x sin (2 x 30) ) / 9.8
R = 1,272.53 m
(ii) The velocity of the jumper after 0.5 s is calculated as follows;
v = u + gt
where;
- v is the final velocity
- u is the initial velocity
in vertical direction:
v = 120 sin(30) - 9.8 x 0.5
v = 55.1 m/s
in horizontal direction:
v = 120 m/s x cos(30)
v = 103.92 m/s
The resultant velocity is;
v = √ (55.1² + 103.92²)
v = 117.6 m/s