Question

LM is the midsegment of trapezoid ABCD. If AB =50 and DC = 135, what is LM? Please show all work in order to recieve full credit for this problem

Answer 1

The length of midsegment LM of the trapezoid is calculated as the average of the two bases AB and DC, yielding a length of 92.5 units.

Step-by-step explanation:

To find the length of the midsegment LM of a trapezoid, we use the properties of the midsegment of a trapezoid. The midsegment of a trapezoid is parallel to the bases and its length is equal to the average of the lengths of the two bases. Therefore, to calculate LM, we use the following formula:

LM = (AB + DC) / 2

Given that AB = 50 and DC = 135, we can substitute these values into our formula:

LM = (50 + 135) / 2

LM = 185 / 2

LM = 92.5

So, the length of the midsegment LM is 92.5 units.

Answer 2

The length of midsegment LM of a trapezoid, with bases AB = 50 units and DC = 135 units, is calculated to be 92.5 units by averaging the lengths of the bases.

Step-by-step explanation:

The question is asking to find the length of midsegment LM of a trapezoid given the lengths of the bases. In a trapezoid, the midsegment is parallel to the bases and its length is the average of the lengths of the two bases. Considering that AB is 50 units and DC is 135 units, the length of midsegment LM can be found using the formula:

LM = (AB + CD) / 2

Placing the given values in the formula:

LM = (50 + 135) / 2

LM = 185 / 2

LM = 92.5

Therefore, the length of the midsegment LM is 92.5 units.