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A student doing an activity lowers a 2.50 kg mass 10.0 m from the top of stadium bleachers. Which represents the amount of work done by the student

User LarsVegas
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The amount of work done by the student is 245 Joules. Option B.

The work done, W, for any object is calculated using the formula:


\[ W = m \cdot g \cdot h \]

where:

-
\( m \) is the mass (2.50 kg),

-
\( g \) is the acceleration due to gravity (approximately 9.8 m/s²),

-
\( h \) is the height (10.0 m).

In this case:


\[ W = 2.50 \, \text{kg} \cdot 9.8 \, \text{m/s}^2 \cdot 10.0 \, \text{m} \]


\[ W = 245 \, \text{Joules} \]

Therefore, the amount of work done by the student is 245 Joules.

The complete question:

A student doing an activity lowers a 2.50 kg mass 10.0 m from the top of stadium bleachers. Which represents the amount of work done by the student

a) 0 J

b) 245 J

c) 2500 J

d) 25,000 J

User Mtveezy
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8.4k points