Final answer:
The slope-intercept form of the equation for line l that reflects the point (5, 5) to (-1, 11) is y = x + 6.
Step-by-step explanation:
To find the slope-intercept form of the equation for line l that reflects the point (5, 5) to (-1, 11), we can first determine the midpoint between these two points, which lies on line l. The midpoint M is given by the average of the x-coordinates and the y-coordinates of the two points. This yields M = ((5 + (-1)) / 2, (5 + 11) / 2) = (2, 8).
The slope of line l is perpendicular to the slope of the line connecting the two points because reflection over a line implies that line is the perpendicular bisector of the segment joining the original and reflected points. The slope between (5, 5) and (-1, 11) is (11 - 5) / (-1 - 5) = 6 / -6 = -1. A line perpendicular to this has a slope that is the negative reciprocal, so the slope of line l is 1.
The equation of a line with slope m and passing through a point (x1, y1) is given by y - y1 = m(x - x1). Applying the point-slope form with our midpoint (2, 8) and slope 1 gives us the equation of line l as y - 8 = 1(x - 2).
Simplifying this into slope-intercept form yields y = x + 6. Therefore, the slope-intercept form of the equation for line l is y = x + 6.