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At the end of meiosis I, one daughter cell will have four copies of chromosome 22, whereas the other will have zero copies of chromosome 22.

User Nicolina
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Final answer:

The question describes nondisjunction, which is a failure of chromosome 22 to separate properly during meiosis I, leading to unequal distribution of chromosomes among the daughter cells. Normally, meiosis should result in four haploid cells each with a single copy of each chromosome.

Step-by-step explanation:

The scenario described suggests a phenomenon known as nondisjunction during meiosis I, where homologous chromosomes fail to separate properly. In a normal meiotic process, homologous chromosomes separate and go to different daughter cells, resulting in each cell having one complete set of chromosomes after meiosis I. As a result, one daughter cell ends up with four copies of chromosome 22 (two tetrads) while the other cell has none, which is an error. Generally, after cytokinesis, each cell would divide again during meiosis II to eventually produce four haploid daughter cells, each with half the DNA of the original parent cell, meaning each cell should have one copy of chromosome 22. These cells would then become gametes, which are involved in sexual reproduction.

Any errors in this process, such as the nondisjunction that led to the observation of a daughter cell with four copies of chromosome 22, can result in conditions such as Down syndrome or other aneuploidies. The process of meiosis includes creation of genetic diversity via random assortment of chromosomes and genetic recombination through crossing over, but it is crucial that the correct number of chromosomes ends up in the gametes for healthy development to occur.

User Greg Demetrick
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