Final answer:
The answers to the given questions are:
a. 262,144 pages, b. 16,384 frames,
c. 262,144 entries, d. 262,144 * sizeof(entry),
e. 26 bits, and) f. 30 bits
Step-by-step explanation:
a. Number of pages:
To calculate the number of pages in the logical address space, we divide the total logical address space by the page size:
Number of pages = Logical address space / Page size
= 4GB / 4 KB = 1024 MB / 4 KB
= 1024 * 1024 KB / 4 KB
= 262,144 pages
b. Number of frames:
Since the total size of the physical address space is 64 MB and the page size is 4 KB, we can calculate the number of frames as:
Number of frames = Physical address space / Page size
= 64 MB / 4 KB = 64 * 1024 KB / 4 KB
= 16,384 frames
c. Number of entries in Page Table:
Since each page has a corresponding entry in the page table, the number of entries in the page table is equal to the number of pages:
Number of entries in Page Table = Number of pages
= 262,144 entries
d. Size of Page Table:
To calculate the size of the page table, we multiply the number of entries in the page table by the size of each entry:
Size of Page Table = Number of entries in Page Table * Size of each entry
= 262,144 entries * sizeof(entry)
= 262,144 * sizeof(entry)
e. Number of bits in Physical Address:
Since there are 16,384 frames in the physical address space and each frame has a size of 4 KB, we can calculate the number of bits in the physical address as:
Number of bits in Physical Address = log2(Number of frames) + log2(Frame size)
= log2(16,384) + log2(4 KB)
= log2(2^14) + log2(2^12)
= 14 + 12
= 26 bits
f. Number of Bits in Logical Address:
Since there are 262,144 pages in the logical address space and each page has a size of 4 KB, we can calculate the number of bits in the logical address as:
Number of bits in Logical Address = log2(Number of pages) + log2(Page size)
= log2(262,144) + log2(4 KB)
= log2(2^18) + log2(2^12)
= 18 + 12
= 30 bits