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P(x)=x^4+2x^3-dx^2-14x+24 if (x-3)

User Fraggley
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The calculated value of d if x - 3 is a factor of p(x) is 13

How to determine the value of d

From the question, we have the following parameters that can be used in our computation:


p(x)=x^4+2x^3-dx^2-14x+24

Also, we have that

x - 3 is a factor

Using the remainder theorem, we have

p(3) = 0

Substitute the known values into the equation


3^4 + 2(3)^3- d (3)^2 - 14(3) + 24 = 0

This gives

117 - 9d = 0

Add 9d to both sides

9d = 117

So, we have

d = 117/9

Evaluate

d = 13

Hence, the value of d is 13

Question

Calculate d in p(x)=x^4+2x^3-dx^2-14x+24 if (x-3) is a factor

User Darren Steinweg
by
8.1k points

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