137k views
2 votes
There are 10 rolls of film in a box and 3 are defective. Two rolls are to be selected without replacement. What is the probability of selecting a defective roll followed by another defective roll?

a) 1/2, or 0.50
b) 1/4, or 0.25
c) 1/120, or about 0.0083
d) 1/15, or about 0.07

User Shersha Fn
by
7.3k points

1 Answer

1 vote

Final answer:

The probability of selecting a defective roll followed by another defective roll can be calculated by multiplying the probabilities of the two events. In this case, the probability is 1/15, or approximately 0.07. The correct answer is D.

Step-by-step explanation:

In this problem, we are choosing two rolls without replacement from a box containing 10 rolls, 3 of which are defective. The probability of selecting a defective roll followed by another defective roll can be calculated as follows:

  1. First, we select one defective roll from the 3 in the box. The probability of selecting a defective roll is 3/10.
  2. After the first roll is selected, there are 9 rolls left in the box, and 2 of them are defective. So the probability of selecting a second defective roll from the remaining 9 rolls is 2/9.
  3. Since the rolls are selected without replacement, we multiply the probabilities of the two events to find the overall probability. So, the probability of selecting a defective roll followed by another defective roll is (3/10) * (2/9) = 6/90 = 1/15, or approximately 0.07 (option d).

User Eladrich
by
7.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories