Final answer:
The Lewis structure for dimethyl ether (CH3OCH3) is H | H H-C-O-C-H | H H
Step-by-step explanation:
The Lewis structure for dimethyl ether (CH3OCH3) can be drawn by following these steps:
- Count the total number of valence electrons in the molecule. For dimethyl ether, we have 4 valence electrons for carbon (C), 1 valence electron for hydrogen (H), and 6 valence electrons for oxygen (O), totaling to 16 valence electrons.
- Place the atoms in the molecule, with the least electronegative atom (carbon) as the central atom.
- Connect the central carbon atom to the oxygen atoms with single bonds.
- Complete the octets of the atoms bonded to the central carbon atom by adding lone pairs of electrons.
- Distribute the remaining electrons as lone pairs on the oxygen atoms.
The Lewis structure of dimethyl ether is therefore:
H
| H
H-C-O-C-H
| H
H