Final answer:
The question pertains to physics, specifically the motion and velocity of two cars under different scenarios. Without the image, we can infer that Car A, when accelerating, will be faster than Car B at a checkpoint if Car B maintains a constant speed. The equation provided is inconsistent as it would not account for Car A's positive acceleration from rest.
Step-by-step explanation:
The question at hand involves analyzing the motion and velocity of two cars under different conditions. Without access to the image, it is not possible to provide a direct response to what Car A should do in response to Car B. However, based on the textual information provided, in scenario (a), if Car A goes over the top at a faster speed than Car B, it would complete the trip around the track in less time. Conversely, in scenario (b), if Car A goes over the top at a slower speed than Car B, it would take longer to complete a trip around the track than Car B.
In the critical thinking scenario, since Car A starts from rest and has a positive, constant acceleration, and Car B travels at a constant speed, by the time they reach the checkpoint together, Car A will be traveling faster as its velocity would have been increasing from zero. The proposed equation for Car A's speed V = Kv0, where K is a constant and V0 is Car B's initial velocity, is logically inconsistent with Car A starting from rest, since if Car A's initial velocity was zero, the equation would always yield a velocity of zero, contradicting the fact that Car A has a positive acceleration and does reach some velocity at the check point.
A velocity vs. distance graph would help visualize the differences in Car A's acceleration and Car B's constant velocity over the distance.