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16 votes
16 votes
The distance ab =?
round to the nearest tenth​

The distance ab =? round to the nearest tenth​-example-1
User Belizzle
by
3.2k points

2 Answers

13 votes
13 votes

Answer:

D≈2.8

Explanation:

A(-3,1) and B(-1,-1)

d=square root of [(x2-x1)^2+(y2-y1)^2]

d=square root of [(-1+3)^2+(-1-1)^2]

d=square root of [8]

d≈2.8

User Alaasdk
by
2.7k points
11 votes
11 votes

Check the picture below.


~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{-3}~,~\stackrel{y_1}{1})\qquad B(\stackrel{x_2}{-1}~,~\stackrel{y_2}{-1})\qquad \qquad d = √(( x_2- x_1)^2 + ( y_2- y_1)^2) \\\\\\ AB=√((~~-1 - (-3)~~)^2 + (~~-1 - 1~~)^2) \implies AB=√((-1 +3)^2 + (-1 -1)^2) \\\\\\ AB=√(( 2 )^2 + ( -2 )^2) \implies AB=√( 4 + 4 ) \implies AB=√( 8 )\implies AB\approx 2.8

The distance ab =? round to the nearest tenth​-example-1
User Darren Gansberg
by
2.9k points