Question

a basketball player has probability 0.75 of making a free throw. explain how you would use each chance device to simulate one free by the player.

Answer 1

The probability that Helen makes both free throws is found by multiplying the probability of making the first shot (75%) by the conditional probability of making the second shot given the first is made (85%), resulting in a 63.75% chance of making both shots.

Step-by-step explanation:

The question we are addressing is: What is the probability that Helen makes both free throws?

Helen has a probability of 0.75, or 75%, of making a free throw. This is represented as P(C) = 0.75 for the first shot. Given that she makes the first shot, the probability that she makes the second shot is P(D|C) = 0.85.

To find the probability of Helen making both shots, we multiply the probability of making the first shot by the probability of making the second shot, given that the first has been made:

P(C and D) = P(C) * P(D|C)
P(C and D) = 0.75 * 0.85
P(C and D) = 0.6375 or 63.75%

Therefore, the probability that Helen makes both free throws is 63.75%.