Final answer:
To determine the inductance L of a 0.60 m long air-filled solenoid with a diameter of 2.8 cm containing 7500 loops, we can use the formula for the inductance of a solenoid. Hence, the inductance of the solenoid is 0.00192 H.
Step-by-step explanation:
To determine the inductance (L) of the solenoid, we can use the formula:
L = μ0 x N^2 x A / l
where μ0 = 4π x 10^-7 T*m/A is the permeability of free space, N is the number of loops (7500), A is the cross-sectional area of the solenoid (π x r^2), and l is the length of the solenoid (0.60 m).
Plugging in the values, we have:
L = (4π x 10^-7 T*m/A) x (7500^2) x (π x (0.028 m)^2) / 0.60 m
Simplifying this expression gives:
L = 0.00192 H