Final answer:
The valid expression for the rate of the reaction is - 1/4 Δ[NH₃]/Δt.
Step-by-step explanation:
The balanced chemical equation shows that 2 mol of N₂O5 must decompose for each 1 mol of O₂ produced and that 4 mol of NO₂ are produced for every 1 mol of O₂ produced. The molar ratios of O₂ to N₂O5 and to NO₂ are thus 1:2 and 1:4, respectively. This means that the rate of change of [N₂O5] and [NO₂] must be divided by its stoichiometric coefficient to obtain equivalent expressions for the reaction rate. For example, because NO₂ is produced at four times the rate of O2, the rate of production of NO₂ is divided by 4. The valid expression for the rate of the reaction is:
B) - 1/4 Δ[NH₃]/Δt