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A reaction A+B⟶C obeys the following rate law:

Rate=k[B]2.
If [A] is doubled, how will the rate change?
A) The rate of the reaction would be doubled.
B) The rate of the reaction would be multiplied by 4.
C) The rate of the reaction would be halved.
D) The rate would remain the same.

User Gahan
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1 Answer

2 votes

Final answer:

Doubling the concentration of reactant A alone will not change the rate of the reaction.

Step-by-step explanation:

Doubling the concentration of reactant A alone would double the reaction rate. However, the rate law for the given reaction is rate = k[B]^2, which means that the rate depends on the square of the concentration of B. Therefore, doubling the concentration of A alone will not change the rate. The correct answer is D) The rate would remain the same.

User OpenStove
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