Question

Maple syrup has a density of 1.325 g/mL, and 100.00 g of maple syrup contains 67 mg of calcium in the form of Ca²⁺ ions. What is the molarity of calcium in maple syrup? At. Mass of Ca is 40.078.

A) 45.4 M
B) 0.017 M
C) 12.6 M
D) 0.022 M
E) 0.89 M

Answer 1

The molarity of calcium in maple syrup is approximately 0.022 M.

Step-by-step explanation:

To calculate the molarity of calcium in maple syrup, we need to convert the mass of calcium to moles and the volume of maple syrup to liters. First, we need to convert the mass of calcium from milligrams to grams by dividing by 1000: 67 mg / 1000 = 0.067 g. Next, we can use the density of maple syrup to convert the volume from grams to milliliters: 100.00 g / 1.325 g/mL = 75.47 mL. Finally, we can convert the volume from milliliters to liters: 75.47 mL / 1000 = 0.07547 L. Now, we can calculate the molarity of calcium using the formula: Molarity (M) = moles of solute (Ca²⁺) / volume of solution (L). Moles of calcium = mass of calcium / molar mass of calcium = 0.067 g / 40.078 g/mol = 0.00167 mol. Molarity of calcium = 0.00167 mol / 0.07547 L = 0.022 M. Therefore, the molarity of calcium in maple syrup is approximately 0.022 M.