Question

Explain the results for the tube in which 1.0 M NaOH was added to benzoic acid. Write an equation for this, using complete structures for all organic sub- stances. Now describe what happened when 6.0 M HCI was added to this same tube and explain this result.

Answer 1

When 1.0 M NaOH is added to benzoic acid, it forms sodium benzoate. When 6.0 M HCl is added to the same tube, the sodium benzoate is converted back to benzoic acid.

Step-by-step explanation:

When 1.0 M NaOH is added to benzoic acid, the benzoic acid will react with the NaOH to form sodium benzoate. The equation for this reaction is:

C6H5COOH(aq) + NaOH(aq) → C6H5COONa(aq) + H2O(l)

When 6.0 M HCl is added to the same tube, the sodium benzoate will react with the HCl to form benzoic acid again. The equation for this reaction is:

C6H5COONa(aq) + HCl(aq) → C6H5COOH(aq) + NaCl(aq)