Final answer:
The hybridization of Sb orbitals in SbCl5 is sp3d.
Step-by-step explanation:
The hybridization of Sb orbitals in the SbCl5 molecule is sp3d. To determine the hybridization, we need to look at the number of electron regions around the central atom, which in this case is Sb. SbCl5 has five electron regions, so it requires five hybrid orbitals. The hybridization scheme that corresponds to this is sp3d.