Final answer:
The total pressure at the bottom of the Chesapeake Bay is approximately 1,516,251 N/m², when considering both the atmospheric pressure and the pressure due to the water column.
Step-by-step explanation:
The total pressure at the bottom of the Chesapeake Bay can be calculated by considering the atmospheric pressure and the pressure due to the water column above. The atmospheric pressure can be assumed to be constant at sea level and is typically around 1 atmosphere (atm).
The pressure due to the water column is given by the equation P = ρgh, where P is the pressure, ρ is the density of water, g is the acceleration due to gravity, and h is the depth of the water column.
Using the given depth of 150 m, we can calculate the pressure due to the water column. The density of seawater is about 1025 kg/m³, and the acceleration due to gravity is approximately 9.8 m/s².
Substituting the values into the equation P = ρgh, we get P = (1025 kg/m³)(9.8 m/s²)(150 m) = 1,516,250 N/m².
To find the total pressure at the bottom of the Chesapeake Bay, we add the atmospheric pressure to the pressure due to the water column.
So the total pressure is approximately 1 atm + 1,516,250 N/m² = 1,516,251 N/m².