Question

Z = √R²+(Xʟ - Xᴄ)²

Z = Impedance
R = Resistance
Xʟ = Inductive reactane
Xᴄ = Capacitive reactane

What is the impedance of an AC-series circuit consisting of an inductor with a reactance of 10 ohms, a capacitor with a reactance of 4 ohms, and a resistor with a resistance of 8 ohms?

A. 22 ohms.
B. 5.29 ohms.
C. 10 ohms.

Answer 1

The impedance of the AC-series circuit is 10 ohms.

Step-by-step explanation:

The impedance of an AC-series circuit consisting of an inductor, a capacitor, and a resistor can be calculated using the formula:

Z = √R² + (XL - XC)²

In this case, R = 8 ohms, XL = 10 ohms, and XC = 4 ohms, so substituting the values into the formula:

Z = √8² + (10 - 4)² = √64 + 36 = √100 = 10 ohms.

Therefore, the impedance of the circuit is 10 ohms.