Final answer:
In a series circuit with different rated capacitors, the total capacitance is always less than any of the individual capacitances.
Step-by-step explanation:
In a series circuit with different rated capacitors, the total capacitance is given by the equation 1/CS = 1/C1 + 1/C2 + 1/C3 + ...
This equation shows that the total capacitance, CS, is always less than any of the individual capacitances, C1, C2, C3, and so on. Therefore, option A is correct.