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1 vote
1

Cᴛ = ----------------------
1/C₁ + 1/C₂ + 1/C₃

When different rated capacitors are connected in series in a circuit, the total capacitance is

A. less than the capacitance of the lowest rated capacitor.
B. greater than the capacitance of the highest rated capacitor.
C. equal to the sum of all the capacitances.

User Manju
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1 Answer

5 votes

Final answer:

In a series circuit with different rated capacitors, the total capacitance is always less than any of the individual capacitances.

Step-by-step explanation:

In a series circuit with different rated capacitors, the total capacitance is given by the equation 1/CS = 1/C1 + 1/C2 + 1/C3 + ...

This equation shows that the total capacitance, CS, is always less than any of the individual capacitances, C1, C2, C3, and so on. Therefore, option A is correct.

User Nagel
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