Final answer:
When more than two inductors of different inductances are connected in parallel in a circuit, the total inductance is equal to the sum of the individual inductances.
Step-by-step explanation:
When more than two inductors of different inductances are connected in parallel in a circuit, the total inductance is equal to the sum of the individual inductances (option C).
This can be derived from the formula:
1/Lᴛ = 1/L₁ + 1/L₂ + 1/L₃
For example, if we have two inductors with inductances L₁ = 2 H and L₂ = 3 H, the total inductance when they are connected in parallel would be:
1/Lᴛ = 1/2 + 1/3 = 5/6
Hence, the total inductance would be:
Lᴛ = 6/5 = 1.2 H