Final answer:
Micah can divide 32 pieces of candy into bags such that each bag has either 1, 2, or 8 pieces. These amounts are divisors of 32, making option C (1, 2, 8) the correct answer.
Step-by-step explanation:
Micah is considering how many pieces of candy could be in each bag for his birthday party based on having a total of 32 pieces to distribute. To determine which options are possible, we have to consider the divisors of 32, which are the numbers that divide evenly into 32 without remainder.
The divisors of 32 are 1, 2, 4, 8, 16, and 32. Thus, the bags could have 1 piece of candy if there are 32 bags, 2 pieces if there are 16 bags, 4 pieces if there are 8 bags, 8 pieces if there are 4 bags, 16 pieces if there are 2 bags, and 32 pieces if there is just 1 bag.
Reviewing the options given:
- A. 1, 4, 9 - 1 and 4 are valid divisors of 32, but 9 is not.
- B. 3, 5, 8 - 8 is a valid divisor of 32, but 3 and 5 are not.
- C. 1, 2, 8 - All these numbers are valid divisors of 32.
- D. 2, 4, 7 - 2 and 4 are valid divisors of 32, but 7 is not.
Therefore, the correct answer would be option C. 1, 2, 8.