Question

a carnot engine takes in 3000 j from its hot reservoir with an associated change in entropy of 6.0 j/k . if the cold reservoir temperature is 430 k , what is |qc| ?

Answer 1

The absolute value of the heat transferred to the cold reservoir in a Carnot engine is approximately 2866.3 J.

Step-by-step explanation:

The formula to calculate the heat transferred to the cold reservoir in a Carnot engine is given by:

|Qc|=|Qh|-W

Where |Qh| is the heat transferred to the hot reservoir and W is the work done by the engine. In this case, the heat transferred to the hot reservoir is 3000 J. Since the change in entropy is given as 6.0 J/K, we can use the formula:

Change in entropy = Qh / Th = 6.0 J/K

Solving for Th, we get Th = Qh / (Change in entropy) = 3000 J / 6.0 J/K = 500 K.

Now, we can calculate the work done by the engine:

W = |Qh| - |Qc| = 3000 J - |Qc|

Substituting the values of Th and Tc into the equation:

500 K / 430 K = 3000 J - |Qc|

Solving for |Qc|, we get |Qc| = 2866.3 J.

Therefore, the absolute value of the heat transferred to the cold reservoir, |Qc|, is approximately 2866.3 J.