Final answer:
Convolving shifted rectangle functions rect(t - 1) and rect(t - 2) results in a triangle function tri(t - 3), based on the given relationship that the convolution of rect(t) with itself yields tri(t).
Step-by-step explanation:
The question relates to the principle of convolution in mathematics, where two functions, in this case rect(t) and tri(t), are integrated to produce a third function. According to given information, if rect(t) is convolved with itself, the result is tri(t).
Now, to answer what the result of rect(t - 1) * rect(t - 2) would be, we consider the properties of convolutions. When a rectangle function is shifted and then convolved with another shifted rectangle function, the result is a triangle function that is also shifted.
Therefore, based on the initial relationship, the convolution of rect(t - 1) with rect(t - 2) would produce a triangle function shifted accordingly, which is tri(t - 3).