Final answer:
The snippet code will result in both 'arrOrigin' and 'copy' arrays displaying [-1, 0, 2, 4, 5, 7, 9]. Both arrOrigin and copy will display the sorted array [-1, 0, 2, 4, 5, 7, 9] because both reference the same array object that was sorted by the bubbleSort method. The correct answer is option a: [-1, 0, 2, 4, 5, 7, 9] [-1, 0, 2, 4, 5, 7, 9].
Step-by-step explanation:
The correct answer is option a: [-1, 0, 2, 4, 5, 7, 9] [-1, 0, 2, 4, 5, 7, 9].
When the bubbleSort method is called on the 'copy' array, it will sort the elements in ascending order. Since 'copy' is just a reference to the 'arrOrigin' array, both arrays will be modified and display the same result.
Therefore, the sorted array will be displayed twice, resulting in [-1, 0, 2, 4, 5, 7, 9] for both arrays.
Both arrOrigin and copy will display the sorted array [-1, 0, 2, 4, 5, 7, 9] because both reference the same array object that was sorted by the bubbleSort method.
The answer would be (-1, 0, 2, 4, 5, 7, 9) for both arrOrigin and copy. This is because arrays in Java are reference types, which means when you assign arrOrigin to copy, you're copying the reference to the original array, not creating a distinct copy of the array. Therefore, any changes you make to copy are also reflected in arrOrigin. Since the bubbleSort method is applied to copy, the original array pointed to by both copy and arrOrigin is sorted.
When the display method is called for both arrOrigin and copy, the array elements have already been sorted and thus both outputs will display the sorted array: [-1, 0, 2, 4, 5, 7, 9].