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assume that ha is a weak acid with a ka of 4.98 x10⁻⁶. if a solution of ha has an initial concentration of 0.856 m, what is the ph of that solution?

User TimJ
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Final answer:

To determine the pH of a solution of a weak acid, we can use the equation pH = -log[H+]. In this case, using an ICE table and the Ka value, we can calculate the equilibrium concentration of [H+] and then use the pH equation to find the pH of the solution. The pH of the solution is approximately 2.744.

Step-by-step explanation:

To determine the pH of a solution of a weak acid, we can use the equation pH = -log[H+], where [H+] is the concentration of the hydronium ions. In this case, we are given the initial concentration of the weak acid (HA) as 0.856 M and its Ka value as 4.98 x 10⁻⁶.

Since HA is a weak acid, we can assume that it will not dissociate completely in water. Using an ICE table and the Ka value, we can calculate the equilibrium concentration of [H+] and then use the pH equation to find the pH of the solution.

Setting up an ICE table for the dissociation of HA:

[HA] -> [H+] + [A-]

Initial: 0.856 M -> 0 + 0

Change: -x -> +x + +x

Equilibrium: 0.856 - x -> x + x

We know that the initial concentration of [HA] is 0.856 M, so the equilibrium concentration of [HA] is also 0.856 M - x.

Using the Ka expression for the dissociation of HA:

Ka = [H+][A-]/[HA]

Since [H+] = x and [A-] = x, we can substitute these values into the expression.

4.98 x 10⁻⁶ = (x)(x)/(0.856 - x)

Simplifying the equation:

x² = 4.98 x 10⁻⁶(0.856 - x)

x² = 4.98 x 10⁻⁶(0.856) - 4.98 x 10⁻⁶x

x² + 4.98 x 10⁻⁶x - 4.98 x 10⁻⁶(0.856) = 0

Solving the quadratic equation using the quadratic formula, we find that x = 0.0018 M.

Therefore, the concentration of [H+] is 0.0018 M. To calculate the pH, we use the equation pH = -log(0.0018) = 2.744.

Therefore, the pH of the solution is approximately 2.744.

User Rumen Georgiev
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