Final answer:
Using Boyle's Law, the final pressure of the gas when the volume changes from 11L at 5.5 atm to 2.8L is calculated to be 21.5 atm.
Step-by-step explanation:
To find the pressure when a certain gas occupies a volume of 2.8L after having previously occupied a volume of 11L at a pressure of 5.5atm, we can use Boyle's Law. Boyle's Law states that the pressure of a given mass of an ideal gas is inversely proportional to its volume when the temperature and amount of gas remain constant. Therefore, the relationship is:
P1 × V1 = P2 × V2
Where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.
Inserting the given values into the equation, we have:
5.5 atm × 11 L = P2 × 2.8 L
To isolate P2 and solve for the unknown final pressure, we divide both sides of the equation by 2.8 L:
P2 = (5.5 atm × 11 L) / 2.8 L
P2 = 21.5 atm
Thus, the final pressure of the gas when it occupies a volume of 2.8L is 21.5atm.