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A die marked with numbers 1,2,2,3,3,3 is rolled three times. Find the probability of occurrence of 1,2 and 3 respectively

a. 1/12
b 1/6
c. 1/36
d. 1/24

User Keyboardr
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1 Answer

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Final answer:

The probability of rolling the numbers 1, 2, and 3 respectively with a die marked as described is the product of the individual probabilities, resulting in 1/36. The correct answer is option c. 1/36

Step-by-step explanation:

The question asks us to find the probability of rolling a die marked with numbers 1,2,2,3,3,3 three times and getting the numbers 1, 2 and 3 respectively. First, we need to determine the probability of each number being rolled.

  • Probability of rolling a 1 (P(1)) = 1/6 (since there's exactly one '1' on the die)
  • Probability of rolling a 2 (P(2)) = 2/6 or 1/3 (since there are two '2's on the die)
  • Probability of rolling a 3 (P(3)) = 3/6 or 1/2 (since there are three '3's on the die)

To find the probability of rolling a 1, then a 2, and then a 3 in that order, we multiply these probabilities together:

P(1 then 2 then 3) = P(1) × P(2) × P(3) = (1/6) × (1/3) × (1/2) = 1/36

Therefore, the correct answer is c. 1/36.

User Haddy
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