Final answer:
The probability of rolling the numbers 1, 2, and 3 respectively with a die marked as described is the product of the individual probabilities, resulting in 1/36. The correct answer is option c. 1/36
Step-by-step explanation:
The question asks us to find the probability of rolling a die marked with numbers 1,2,2,3,3,3 three times and getting the numbers 1, 2 and 3 respectively. First, we need to determine the probability of each number being rolled.
- Probability of rolling a 1 (P(1)) = 1/6 (since there's exactly one '1' on the die)
- Probability of rolling a 2 (P(2)) = 2/6 or 1/3 (since there are two '2's on the die)
- Probability of rolling a 3 (P(3)) = 3/6 or 1/2 (since there are three '3's on the die)
To find the probability of rolling a 1, then a 2, and then a 3 in that order, we multiply these probabilities together:
P(1 then 2 then 3) = P(1) × P(2) × P(3) = (1/6) × (1/3) × (1/2) = 1/36
Therefore, the correct answer is c. 1/36.