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Which of the following is equivalent to \[(x^2 +1)+(2x -1)\] ?

User Fishera
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Final answer:

The equivalent form of \((x^2 +1)+(2x -1)\) is \(x^2 + 2x\), which is found by combining like terms.

Step-by-step explanation:

The expression \((x^2 +1)+(2x -1)\) consists of two parts that can be combined together by performing algebraic addition. When we combine like terms, we group the x-squared terms and the constant terms separately, and the x terms after that. So, we add the constant terms (1 and -1) and the x terms (2x) to the x-squared term \(x^2\).

Step by step, it looks like this:

  • Combine the x-squared terms: \(x^2 + (nothing) = x^2\).
  • Combine the x terms: \((nothing) + 2x = 2x\).
  • Combine the constant terms: \(1 + (-1) = 0\).

After combining the like terms, we get:

\(x^2 + 2x + 0\)

Since adding zero does not change the value, we can simplify it further to:

\(x^2 + 2x\)

This is the simplified equivalent form of the original expression.

User ProNotion
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