134k views
1 vote
A 28.9 mL aliquot of a 3.2 M Hal stock solution is diluted to a 454.0 mL of solution. What is the HCl concentration of the diluted solution

a.) 4.9 M
b.) .093 M
c.) .2 M
d.) .5 M

User JKillian
by
9.0k points

1 Answer

0 votes

Final answer:

The final concentration of HCl after dilution is approximately 0.204 M, which we round to 0.20 M due to significant figures.

Step-by-step explanation:

To determine the final concentration of the diluted HCl solution, we need to use the concept of dilution of concentrated solutions. The formula for calculating the final concentration after dilution is:

(stock concentration) × (volume of aliquot) / (final volume) = final concentration

Plugging in the values provided:

((3.2 M) × (28.9 mL)) / (454.0 mL) = final concentration

We first need to convert mL to L to ensure consistent units. So, 28.9 mL is 0.0289 L and 454.0 mL is 0.454 L.


((3.2 M) × (0.0289 L)) / (0.454 L) = final concentration

Carry out the multiplication and division to find the final concentration:

(0.09248 M) / (0.454 L) ≈ 0.204 M

Therefore, the final concentration of the diluted HCl solution is approximately 0.204 M, which we would round to 0.20 M to reflect the significant figures from the initial concentration.

User Jah Yusuff
by
8.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.