Question

How many mL of a .5 M AgNO3 solution will provide 100 g of AgNO3

a.) 300 mL
b.) 180 mL
c.) 1200 mL
d.) 250 mL

Answer 1

To provide 100 g of AgNO3, you would need 1200 mL of a 0.5 M AgNO3 solution.

Step-by-step explanation:

To find the volume of the 0.5 M AgNO3 solution needed to provide 100 g of AgNO3, we can use the formula:

molarity (M) = moles/volume (L)

First, we need to calculate the moles of AgNO3 using its molar mass:

AgNO3 molar mass = 107.87 + (14.01 + 16.00 * 3) = 169.87 g/mol

moles of AgNO3 = mass/volume = 100 g / 169.87 g/mol = 0.589 mol

Next, we can use the molarity formula to find the volume:

0.5 M = 0.589 mol/volume (L)

volume (L) = 0.589 mol / 0.5 M = 1.18 L = 1180 mL

Therefore, option (c) 1200 mL is the correct answer.