Question

A chemist puts 42.7 g of sucrose into a 500 mL volumetric flask and pours in water until the solution volume is 500.0 mL. What is the concentration of sucrose in the solution> MM = 342.3 g/mol

a.) .250 M
b.) .237 M
c.) 4.22 M
d.) 4.74 x 10⁻⁴ M

Answer 1

The concentration of sucrose in the solution is approximately 0.2494 M.

Step-by-step explanation:

The concentration of sucrose in the solution can be calculated using the formula:

Concentration (M) = moles of solute / volume of solution (L)

First, we need to convert the mass of sucrose to moles using the molar mass:

Moles of sucrose = mass of sucrose / molar mass

Moles of sucrose = 42.7 g / 342.3 g/mol

Moles of sucrose = 0.1247 mol

Next, we need to convert the volume of the solution to liters:

Volume of solution = 500.0 mL * 1 L/1000 mL = 0.5 L

Finally, we can calculate the concentration of sucrose:

Concentration = 0.1247 mol / 0.5 L = 0.2494 M

Therefore, the concentration of sucrose in the solution is approximately 0.2494 M.