Final answer:
To find the density of an object submerged in water, we apply Archimedes' Principle and use the difference between the actual weight and the apparent weight. However, the provided apparent weight being greater than the actual weight of the object in air suggests an error because it defies the principle that a submerged object weighs less due to the buoyant force.
Step-by-step explanation:
To calculate the density of the object, we can apply Archimedes' Principle, which states that the buoyant force on a submerged object is equal to the weight of the fluid it displaces. Since the object is completely submerged in freshwater and its apparent weight is given, we can use this information to find the volume of water displaced, which is equivalent to the volume of the object.
First, we need to determine the actual weight of the object in newtons, which we can get by multiplying its mass (1 kg) by the acceleration due to gravity (approximately 9.8 m/s2). This gives us an actual weight of 9.8 N. The object's apparent weight in water is 10.2 N. Since the apparent weight is the actual weight minus the buoyant force, and the object's actual weight is greater than its apparent weight, there must be an error in the given values as this situation is physically impossible.
If we were given correct values, we would have proceeded by calculating the weight of the fluid displaced using the difference between the object's actual weight and its apparent weight. With the volume of the displaced water, we would then find the density of the object by dividing the mass of the object by the volume of water displaced, using the formula ρ = m/V.