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3x^2 + 8 = -316 using the square root method

User Myisha
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Answer:x = ±√(-108)

Explanation:

To solve the equation 3x^2 + 8 = -316 using the square root method, first, we isolate the x^2 term by subtracting 8 from both sides:

3x^2 = -324

Next, divide both sides by 3 to isolate the x^2 term:

x^2 = -324/3

x^2 = -108

Taking the square root of both sides, we have:

x = ±√(-108)

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