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What is the total volume of the mixture of hydrogen gas and oxygen gas can be obtained from the electrolysis of 110.0 grams of water at 25.0°C and 1.00 atm pressure according to the chemical equation shown below?

2 H₂O(l)→ 2 H₂(g) + O₂(g)
a.149 L
b.224 L
c.74.7L
d.447 L

1 Answer

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Final answer:

To find the total volume of the mixture of hydrogen gas and oxygen gas obtained from the electrolysis of water, use Avogadro's law and the balanced equation for the reaction. Convert the mass of water to moles, use the mole ratio to find the moles of hydrogen and oxygen gas, then use Avogadro's law to find the total volume.

Step-by-step explanation:

To find the total volume of the mixture of hydrogen gas and oxygen gas obtained from the electrolysis of water, we need to use Avogadro's law. The balanced equation for the electrolysis of water is 2 H₂O(l) → 2 H₂(g) + O₂(g). From the equation, we can see that 2 moles of water produce 2 moles of hydrogen gas and 1 mole of oxygen gas.

Given that 110.0 grams of water is electrolyzed, we first need to convert the grams of water to moles of water by dividing the given mass by the molar mass of water (18.02 g/mol). After finding the moles of water, we can use the mole ratio from the balanced equation to calculate the moles of hydrogen gas and oxygen gas produced. Finally, we can use Avogadro's law to find the total volume of the mixture of hydrogen gas and oxygen gas by multiplying the number of moles by the molar volume of an ideal gas at the given temperature and pressure.

Using this method, the total volume of the mixture of hydrogen gas and oxygen gas obtained from the electrolysis of 110.0 grams of water is 149 L.

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