Question

1|>try:

2|>>x = some_function()
3|>>y = some_other_function()
4|>>print(x * y)
5|>except TypeError:
6|>>print("An expected error occurred!")
7|>except NameError:
8|>>print("An expected error occurred!")
9|>except IndexError:
10|>>print("An expected error occurred!")
11|>except Exception as ex:
12|>>print("An unexpected error occurred:", ex)
Q: Which of the following code segments will always perform exactly the same as the segment above?

Answer 1

The alternative code segment must catch the same specific exceptions as the original and handle all other exceptions generically. It would consolidate the anticipated exceptions into one block and include a generic except clause.

Step-by-step explanation:

The provided code snippet implements exception handling in Python. It attempts to execute two functions and multiply their results. However, it also anticipates and catches specific exceptions like TypeError, NameError, and IndexError, providing an error message for each. If another exception is raised that is not one of the specified types, it is caught by the generic Exception clause and a message including the exception details is printed.

To have code that always performs exactly the same as the segment above, it would need to cover all the same exceptions with specific messages and then catch any other exception generically. So, the alternative code block would look something like this:

try:
x = some_function()
y = some_other_function()
print(x * y)
except (TypeError, NameError, IndexError):
print("An expected error occurred!")
except Exception as ex:
print("An unexpected error occurred:", ex)

This revision consolidates the handling of the anticipated TypeError, NameError, and IndexError into a single block, which simplifies the code while maintaining the same functionality.