Question

Use the Hardy-Weinberg equations: p + q = 1 and

p2 + 2pq + q2 = 1. If the dominant allele frequency is 0.8, then what percent of the population will be homozygous dominant?
A. 0.32
B. 0.16
C. 0.04
D. 0.64
E. 0.40

Answer 1

To calculate the percent of the population that will be homozygous dominant, we need to find the frequency of the dominant allele. Given that the dominant allele frequency is 0.8, the frequency of the homozygous dominant genotype (AA) is 0.64, which corresponds to 64% of the population.

Step-by-step explanation:

To calculate the percent of the population that will be homozygous dominant, we need to find the frequency of the dominant allele.

Given that the dominant allele frequency is 0.8, we can calculate the recessive allele frequency (q) by subtracting the dominant allele frequency from 1: q = 1 - 0.8 = 0.2.

The Hardy-Weinberg equation for the frequency of the homozygous dominant genotype (AA) is p2, where p is the dominant allele frequency. Plugging in the value of p, we get: AA frequency = (0.8)2 = 0.64.

To convert this frequency to a percentage, we multiply by 100: AA percentage = 0.64 * 100 = 64%.