Question

Use the Hardy-Weinberg equations: p + q = 1 and

p2 + 2pq + q2 = 1. If the dominant allele frequency is 0.8, then what percent of the population will be heterozyous?
A. 0.32
B. 0.16
C. 0.64
D. 0.04
E. 0.40

Answer 1

The frequency of the heterozygous genotype (Aa) can be calculated using the Hardy-Weinberg equation and the given dominant allele frequency of 0.8. The answer is 32%.

Step-by-step explanation:

To calculate the frequency of the heterozygote genotype (Aa), we can use the equation p + q = 1, where p represents the frequency of the dominant allele and q represents the frequency of the recessive allele.

Since the dominant allele frequency is given as 0.8, we can calculate q as follows:

q = 1 - p = 1 - 0.8 = 0.2

Therefore, the heterozygous genotype frequency (Aa) would be 2pq = 2(0.8)(0.2) = 0.32, or 32%.