224k views
0 votes
What is the molarity of a solution of sucrose, C₁₂H₂₂O₁₁, that contains 125 g of sucrose in 3.50 l of solution? (molar mass of C₁₂H₂₂O₁₁ = 342.34 g/mol)

User Pinochle
by
7.9k points

1 Answer

5 votes

Final answer:

To calculate the molarity of a sucrose solution, divide the moles of sucrose by the volume of the solution. With 125 g of sucrose and a solution volume of 3.50 L, the molarity is approximately 0.1043 M.

Step-by-step explanation:

To find the molarity of a sucrose solution, we can use the relationship molarity = moles of solute ∕ liters of solution. First, we need to calculate the number of moles of sucrose using the molar mass. The molar mass of sucrose, C₁₂H₂₂O₁₁, is given as 342.34 g/mol.

Moles of sucrose = mass of sucrose (g) ∕ molar mass (g/mol).

Moles of sucrose = 125 g ∕ 342.34 g/mol = 0.365 moles (approximately).

Now, we divide the moles of sucrose by the volume of the solution in liters:

Molarity (M) = 0.365 moles ∕ 3.50 L = 0.1043 M (approximately).

Thus, the molarity of the sucrose solution is approximately 0.1043 M.

User Borancar
by
7.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.