Final answer:
The speed of water in the second part of the pipe, with a cross-sectional area of 18.0 m², is found to be approximately 1.32 m/s when applying the continuity equation that relates the flow rate before and after the expansion.
Step-by-step explanation:
To find the speed of the water in the second part of the pipe, we can use the principle of conservation of mass. The equation to use is:
A1V1 = A2V2
Where A1 and V1 are the cross-sectional area and speed of water in the first part of the pipe, and A2 and V2 are the cross-sectional area and speed of water in the second part of the pipe.
Given that the initial cross-sectional area (A1) is 2 m², the initial speed (V1) is 12.2 m/s, and the final cross-sectional area (A2) is 18.0 m², we can plug in these values to find the speed of the water in the second part of the pipe:
2 m² * 12.2 m/s = 18.0 m² * V2
Solving for V2, we get:
V2 = 2 m² * 12.2 m/s / 18.0 m²
V2 ≈ 1.32 m/s