Final answer:
To have the same number of moles of oxygen as in 112 grams of sulfur, 55.84 grams of oxygen is required, based on their respective molar masses of 32.07 g/mol for sulfur and 16.00 g/mol for oxygen.
Step-by-step explanation:
The student is asking how much mass of an oxygen atom is needed to have the same number of moles as in 112 grams of sulfur. The molar mass of sulfur (S) is approximately 32.07 g/mol. To find the number of moles in 112g of sulfur, you divide the mass by the molar mass:
112 g S × (1 mol S / 32.07 g S) = 3.49 mol S
Since we want the same number of moles of an oxygen atom, and knowing that the molar mass of oxygen (O) is approximately 16.00 g/mol, we can calculate the mass:
3.49 mol O × (16.00 g O / 1 mol O) = 55.84 g O
The mass of an oxygen atom that contains the same number of moles as 112g of sulfur is therefore 55.84 grams.