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What is the correct form of the partial fraction decomposition for (35-27x)/4x²+28x

O A/4x + B/x+7
O A/4x² + B/28x
O (Ax+B)/4x + C/x+7
O (Ax+B)/4x² + C/28x

User YTKColumba
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1 Answer

4 votes

Final answer:

The correct form of the partial fraction decomposition for (35-27x)/(4x²+28x) is (Ax+B)/(4x² + Cx) + (D/x + E/(x+7)). To find the values of A, B, C, D, and E, we need to rewrite the expression and equate the numerators and denominators. After solving the resulting system of equations, we can determine the values of the coefficients.

Step-by-step explanation:

The correct form of the partial fraction decomposition for (35-27x)/(4x²+28x) is (Ax+B)/(4x² + Cx) + (D/x + E/(x+7)).

To find the values of A, B, C, D, and E, we need to rewrite the expression and equate the numerators and denominators. After solving the resulting system of equations, we can determine the values of the coefficients.

  1. First, factor the denominator: 4x² + 28x = 4x(x+7)
  2. Write the expression as a sum of two fractions: (35-27x)/(4x²+28x) = A/(4x) + B/(x+7)
  3. Combine the fractions and equate the numerators and denominators:(35-27x)/(4x²+28x) = (A(x+7) + B(4x))/(4x(x+7))
  4. Equate the numerators: 35-27x = (A(x+7) + B(4x))
  5. Equate the denominators: 4x²+28x = 4x(x+7)
  6. Solve the resulting system of equations to find the values of A, B, C, D, and E.
User Dave Causey
by
8.3k points
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