Final answer:
The pressure in the tank is approximately 202.49 J/L.
Step-by-step explanation:
To find the pressure in the tank, we can use the ideal gas law, which states that PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature in Kelvin. We are given the volume of the tank (6.00 L), the number of moles of nitrogen gas (16.5 grams), and the temperature (385 K).
First, we need to convert the mass of nitrogen gas to moles. The molar mass of nitrogen gas (N2) is 28 grams/mol, so:
moles = mass / molar mass = 16.5 g / 28 g/mol = 0.589 mol
Next, we can substitute the values into the ideal gas law equation:
P * 6.00 L = 0.589 mol * 8.314 J/(mol·K) * 385 K
Now solve for P:
P = (0.589 mol * 8.314 J/(mol·K) * 385 K) / 6.00 L = 202.49 J/L
The pressure in the tank is approximately 202.49 J/L.