Final answer:
The molarity of potassium ions in a 0.122 M K₂CrO₄ solution is 0.244 M, as each unit of K₂CrO₄ produces two potassium ions upon dissociation.
Step-by-step explanation:
The molarity of potassium ions in a 0.122 M K₂CrO₄ solution can be calculated based on the fact that each formula unit of K₂CrO₄ produces two potassium ions (2 K⁺) when it dissociates in solution. Therefore, we need to multiply the molarity of the K₂CrO₄ solution by the number of potassium ions per formula unit to find the molarity of potassium ions.
To calculate:
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- Molarity of K₂CrO₄ solution = 0.122 M
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- Number of potassium ions per formula unit = 2
Thus, the molarity of potassium ions is 0.122 M multiplied by 2, which equals 0.244 M K⁺ ions.