Final answer:
The molality of lithium ions in a 0.302 m solution of Li2PO4, which completely dissociates, is 0.604 m because each unit of Li2PO4 produces two lithium ions.
Step-by-step explanation:
The molality of lithium ions in a 0.302 m solution of Li2PO4 that dissociates completely can be determined by considering the dissociation equation:
Li2PO4 → 2 Li+ + PO43-
Since each formula unit of Li2PO4 produces two Li+ ions upon dissociation, the molality of lithium ions will be twice the molality of the Li2PO4 solution. Therefore, the molality of lithium ions is:
0.302 m × 2 = 0.604 m