Final answer:
The translational speed of the object moving uniformly around a circular path of radius 20.0cm, completing one revolution every 2.00s, is approximately 0.314 meters per second (m/s).
Step-by-step explanation:
To calculate the translational speed of an object moving uniformly around a circular path with a radius of 20.0 cm (0.2 m), completing one revolution every 2.00 seconds, we will use the formula for circular motion. The speed (v) can be found using the relationship v = 2πr / T, where r is the radius and T is the period of revolution.
First, let's convert the radius to meters, since SI units are standard in physics:
Radius (r) = 20.0 cm = 0.20 m (since 1 m = 100 cm)
Next, the period (T) is given as:
Period (T) = 2.00 s
Now we'll substitute these values into the formula:
v = 2πr / T = (2 * π * 0.20 m) / 2.00 s
Simplify the units and calculate the speed:
v = (π * 0.20 m/s) ≈ 0.314 m/s
Thus, the translational speed of the object is approximately 0.314 meters per second (m/s).