Question

After a long trip, a bird decides to take a break and lands on one of the wires of an electric power transmission line. the wire carries a current of 0.98 ka and its resistance per unit length is 45 μω/m. calculate the potential difference between the bird's feet if the distance along the wire is 5 cm.____

Answer 1

The potential difference between the bird's feet when it lands on a wire carrying a current of 0.98 kA and a resistance per unit length of 45 μΩ/m over a 5 cm distance is 2.205 mV.

Step-by-step explanation:

To calculate the potential difference between the bird's feet, we can use Ohm's law, which is V = IR, where V is the potential difference, I is the current, and R is the resistance. In this case, we are given the current I = 0.98 kA (which is 980 A), and the resistance per unit length is 45 μΩ/m (or 0.000045 Ω/m). The distance between the bird's feet along the wire is 5 cm (which is 0.05 m).

First, we calculate the total resistance between the bird's feet:

R = resistance per unit length × distance = 0.000045 Ω/m × 0.05 m = 0.00000225 Ω.

Now we can calculate the potential difference V:

V = IR = 980 A × 0.00000225 Ω = 0.002205 V or 2.205 mV.

Therefore, the potential difference between the bird's feet is 2.205 mV.